Question

What is the length of u and v in this 30-60-90 triangle

Answer 1

Answer:

option 2

Step-by-step explanation:

Using trigonometric ratio:

$Cos \ 60 = \frac{adjacent } {hypotenuse} \\\\\frac{1}{2} = \frac{4}{u}\\\\1 \times u = 2 \times 4 \\\\u = 8$

Now using Pythagoras theorem we will find v

$8^2 = 4^2 + v^2\\\\64 = 16 + v^2\\\\v^2 = 64 - 16 \\\\v = \sqrt{48} = \sqrt{16 \times 3} = \sqrt{4^2 \times 3 } = 4\sqrt{3}$

Answer 2

By using trigonometric relations, we will see that v = 4*√3 and u = 8

How to get the missing lengths?

Here we have a right triangle, we can use trigonometric relations to find the missing sides.

We can see that v is the opposite cathetus of the 60° angle, then we can use the relation:

tan(a) = (opposite cathetus)/(adjacent cathetus)

Replacing what we know, we get:

tan(60°) = v/4

4*tan(60°) = v = 4*√3

To get the value of u, we use:

cos(a) = (adjacent cathetus)/(hypotenuse).

cos(60°) = 4/u

u = 4/cos(60°) = 2*4 = 8

Then we have:

v = 4*√3

u = 8

If you want to learn more about triangles, you can read:

https://brainly.com/question/17972372