Respuesta :

Answer:

5x+4y-18=0.

Explanation:

1. the common view of the formula is:

[tex]\frac{x-x_1}{x_2-x_1} =\frac{y-y_1}{y_2-y_1};[/tex]

2. according to the formula above the required equation is:

[tex]\frac{x-2}{-2-2} =\frac{y-2}{5-2}; \ <=> \ 5x+4y-18=0.[/tex]

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