X
ſocm
Jicm
A) 2V5 cm
B) V13 cm
D) V19 cm
C) 1 cm
ASAP
![X ſocm Jicm A 2V5 cm B V13 cm D V19 cm C 1 cm ASAP class=](https://us-static.z-dn.net/files/d47/16249251a0bcc725221f74f3981d12c1.png)
Answer:
using pythagoras theorem
hyp 2=opp 2+adj 2
=( √6)(√6)+(√7)(√7)
hyp 2=13
hyp=√13
Given:
A right angle triangle with legs [tex]\sqrt{6}[/tex] cm and [tex]\sqrt{7}[/tex] cm. The length of the hypotenuse is x.
To find:
The value of x.
Solution:
Pythagoras theorem: In a right angle triangle,
[tex]Hypotenuse^2=Base^2+Perpendicular^2[/tex]
Using the Pythagoras theorem, we get
[tex]x^2=(\sqrt{7})^2+(\sqrt{6})^2[/tex]
[tex]x^2=7+6[/tex]
[tex]x^2=13[/tex]
Taking square root on both sides, we get
[tex]x=\sqrt{13}[/tex] [Because side length is always positive]
The measure of hypotenuse is [tex]\sqrt{13}[/tex] cm.
Therefore, the correct option is B.