Question

select the correct answer
what is the left hand limit of g(x)=
$\frac{ {x}^{2} - 25 }{x - 5}$
as x aproaches 5​

Answer 1

10

Step-by-step explanation:

$\displaystyle \lim_{x \to 5} \left(\dfrac{x^2 - 5}{x - 5} \right)= \lim_{x \to 5} \dfrac{(x+5)(x-5)}{(x-5)}$

or

$\displaystyle \lim_{x \to 5} (x + 5) = 10$