Complete Question
Complete Question is attached below
Answer:
Option A
Explanation:
From the question we are told that:
inner Diameter of pipe [tex]d_i=100^c[/tex]
Thickness [tex]t=50mm[/tex]
Outer diameter of pipe [tex]d_o=1.1m[/tex]
Length [tex]l=5m[/tex]
Temperature [tex]T_i=130^oC[/tex]
Generally the equation for Heat Balance is mathematically given by
[tex]q*\pi d_oL=mC_p(T_i-T_o)[/tex]
Therefore
[tex]T_o=T_i+\frac{q*\pi d_oL}{mC_p}[/tex]
[tex]T_o=130+\frac{100*3.142 *1.1*5}{0.5*4000}[/tex]
[tex]T_o=129.136^oC[/tex]
Therefore the exit temperature of the water.is [tex]T_o=129.136^oC[/tex]
Option A