Answer: The correct option is (B) 0.875 Ω.
Explanation:
Equivalent resistance: It is defined as the sum of the all resistance present in the circuit.
There are two conditions:
(1) Resistors in series
Equivalent resistance, [tex]R_s=R_1+R_2+R_3+R_4........R_n[/tex]
(2) Resistors in parallel
Equivalent resistance, [tex]R_p=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\frac{1}{R_4}........\frac{1}{R_n}[/tex]
According to the given circuit, the resistors are in parallel arrangement.
Given:
[tex]R_A=2.00\Omega\\\\R_B=4.00\Omega\\\\R_C=8.00\Omega[/tex]
Thus,
Equivalent resistance will be:
[tex]R_p=\frac{1}{R_A}+\frac{1}{R_B}+\frac{1}{R_C}\\\\R_p=\frac{1}{2.00}+\frac{1}{4.00}+\frac{1}{8.00}\\\\R_p=0.875\Omega[/tex]
Therefore, the equivalent resistance of the circuit is 0.875 Ω.
