Question

A 15.00 resistor and 7.00 resistor
are connected in parallel to an emf
source. A current of 1.50 A is in the 7.00
2 resistor. What is the potential
difference across the source?

Answer 1

The potential difference across the source will be 7.158 V.Ohm's law principle is applied.

What is ohm’s law?

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

An emf source is connected in parallel to the equivalent resistance of a 15.00 resistor and a 7.00 resistor is:

$\rm \frac{1}{R_{eq}} =\frac{1}{R_1} +\frac{1}{R_2} \\\\ \rm \frac{1}{R_{eq}} =\frac{1}{15} +\frac{1}{7} \\\\ R_{eq} =4.77281 \ ohm$

This current-voltage connection may be expressed mathematically as, The Equation of ohm's Law

$\rm E_{eq}=I_{eq}R{eq}\\\\ \rm E_{eq}= 1.50 \ A \times 4.772 \ ohm \\\\ E_{eq}= 7.158 \ V$

Hence, the potential difference across the source will be 7.158 V.

To learn more the ohm's law refer to the link;

https://brainly.com/question/796939

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