Answer:
As it is given that the initial concentration of sulfuric acid is 0.010 M.
Hence, the ICE table for first dissociation of sulfuric acid is as follows.
Initial: 0.010 0 0
Change: -0.010 +0.010 +0.010
Equilibrium: 0 0.010 0.010
When second dissociation of sulfuric acid occurs which is partial then the ICE table will be as follows.
Initial: 0.010 0 0.010
Change: -x +x +x
Equilibrium: 0.010 - x x 0.010 + x
Since, it is given that . Hence, formula for is as follows.
x = 0.0045
Hence, by using the equilibrium concentrations from the table and value of x we get the following.
= x,
= 0.0045 M
= 0.010 - x
= 0.010 - 0.0045
= 0.0055 M
= 0.010 + x
= 0.010 + 0.0045
= 0.0145 M
Explanation:
