Answer:
Slope of the line perpendicular to the given line = 2/3
Step-by-step explanation:
The product of the slopes of lines perpendicular to each other is - 1
That is,
[tex]slope_{1} \times slope _ 2 = - 1\\[/tex]
Given equation of the line :
3x + 2y = 7
2y = - 3x + 7
[tex]y = -\frac{3}{2}x + \frac{7}{2}[/tex]
[tex]Therefore, \ slope \ of \ the \ given \ line \ , slope _1 = \ -\frac{3}{2}[/tex]
Find slope of the line perpendicular to the given line:
[tex]\frac{-3}{2} \times slope_2 = - 1\\\\slope_2 = - 1 \times \frac{2}{-3} = \frac{2}{3}[/tex]
