Question

PLEASE I REALLY NEED HELP


Plans for a new school call for classrooms directly across the hall from each other to be congruent. This computer printout shows a math classroom. If the vertices of a science classroom are located at (-3x¹,y¹). (-3x²,y²), (-3x³, y³), and (-3x⁴, y⁴), will the science classroom be congruent to the math classroom?​

Answer 1

The lengths of the horizontal sides of the science class is larger than the

length of the horizontal side of the math class.

• The correct option is; No, the the transformation applied was not a rigid motion.

Reasons:

The given vertices of the science classroom are;

(-3·x₁, y₁), (-3·x₂, y₂), (-3·x₃, y₃), and (-3·x₄, y₄)

The coordinates of the vertices math classroom are;

(x₁, y₁), (x₂, y₂), (x₃, y₃), and (x₄, y₄)

Whereby x₁ = x₄, we have;

Length of the vertical side of the rectangular math class = y₁ - y₄

Length of the horizontal side, $L_M$ = x₂ - x₁

Similarly;

The length of the horizontal side of the science class is, $L_S$ = -3·x₂ - (-3·x₁)

Therefore;

$L_S$ = 3·(x₁ - x₂) = $\mathbf{3 \cdot L_M}$

The length of a side of the science is three times the length of the side of

the math class, which gives that the dimensions of the science class are not

the same as the the dimensions of the math class.

Therefore;

The science class and the math class are not congruent

• The the correct option is, no the transformation that gives the science class from the math class is not a rigid transformation.

Learn more about non-rigid transformation here:

https://brainly.com/question/2396426

Answer 2

Answer:

Its the other no then because the first guy said its the top right and it is wrong so it is the bottom left

Step-by-step explanation:

please tell me if im correct