Question

:
What is the x-intercept of the graph of the function f(x) = x2 - 16x + 64?
0 (-8,0)
O (0,8)
(8,0)
(0, -8)

Answer 1

Answer:

$(8,0)$

Step-by-step explanation:

Hope it is helpful....

Answer 2

The x-intercept of f(x) = x² - 16x + 64 is (8, 0)

X-intercept of a graph

The x-intercept is the point at which the graph crosses the x-axis. The x-intercept is when y = 0. Therefore, let's find the x-intercept of f(x) = x² - 16x + 64.

f(x) = x² - 16x + 64

0 = x² - 16x + 64

x² - 8x - 8x + 64 = 0

x(x - 8) - 8(x - 8) = 0

(x - 8)(x - 8) = 0

x = 8

Therefore, the x-intercept of f(x) = x² - 16x + 64 is (8, 0)

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