Answer:
[tex]\frac{m_{O}}{m_{Br}}=0.2[/tex]
Explanation:
Hello there!
In this case, according to the description, it turns out possible for us to calculate the required ratio by performing the following ratio:
[tex]\frac{m_{O}}{m_{Br}}[/tex]
Thus, we plug in the given masses to obtain:
[tex]\frac{m_{O}}{m_{Br}}=\frac{3.404g}{17g}\\\\\frac{m_{O}}{m_{Br}}=0.2[/tex]
Regards!