Question

HELP!!!! if 3.50 moles of sodium hydroxide reacts with excess lead(II) nitrate, how many moles of Pb(OH)2 are produced?

Answer 1

Answer: 1.5 moles of $Pb(OH)_2$ are produced.

Explanation:

We are given:

Moles of sodium hydroxide = 3.50 moles

The given chemical equation follows:

$Pb(NO_3)_2(aq)+2NaOH(aq)\rightarrow Pb(OH)_2(s)+2NaNO_3(aq)$

By stoichiometry of the reaction:

If 2 moles of NaOH produces 1 mole of $Pb(OH)_2$

So, 3 moles of NaOH will produce = $\frac{1}{2}\times 3=1.5mol$ of $Pb(OH)_2$

Hence, 1.5 moles of $Pb(OH)_2$ are produced.