Answer: The mass of water produced is 180.02 g
Explanation:
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
Given mass of HF = 600.0 g
Molar mass of HF = 20.01 g/mol
Plugging values in equation 1:
[tex]\text{Moles of HF}=\frac{600.0g}{20.01g/mol}=29.98 mol[/tex]
The given chemical equation follows:
[tex]SiO_2+6HF\rightarrow H_2SiF_6+2H_2O[/tex]
By the stoichiometry of the reaction:
If 6 moles of HF produces 2 moles of water
So, 29.98 moles of HF will produce = [tex]\frac{2}{6}\times 29.98=9.99mol[/tex] of water
Molar mass of water = 18.02 g/mol
Plugging values in equation 1:
[tex]\text{Mass of water}=(9.99mol\times 18.02g/mol)=180.02g[/tex]
Hence, the mass of water produced is 180.02 g
