Given:
[tex]a=-\dfrac{3}{4}[/tex]
[tex]b=\dfrac{4}{5}[/tex]
To verify:
[tex]a\div b\neq b\div a[/tex]
Solution:
We have,
[tex]a=-\dfrac{3}{4}[/tex]
[tex]b=\dfrac{4}{5}[/tex]
Now,
[tex]a\div b=\dfrac{a}{b}[/tex]
[tex]a\div b=\dfrac{-\dfrac{3}{4}}{\dfrac{4}{5}}[/tex]
[tex]a\div b=-\dfrac{3}{4}\times \dfrac{5}{4}[/tex]
[tex]a\div b=-\dfrac{15}{16}[/tex] ...(i)
And,
[tex]b\div a=\dfrac{b}{a}[/tex]
[tex]b\div a=\dfrac{\dfrac{4}{5}}{-\dfrac{3}{4}}[/tex]
[tex]b\div a=\dfrac{4}{5}\times (-\dfrac{4}{3})[/tex]
[tex]b\div a=-\dfrac{16}{15}[/tex] ...(ii)
From (i) and (ii), it is clear that
[tex]a\div b\neq b\div a[/tex]
Hence verified.