Given:
One of two complementary angles is 35º larger than the other.
To find:
The measure of both angles.
Solution:
Let x degrees be the measure of smaller angle. Then the measure of larger angle is:
[tex]\text{Larger angle}=(x+35)^\circ[/tex]
We know that the sum of complimentary angles is always 90 degrees. So,
[tex]x^\circ+(x+35)^\circ=90^\circ[/tex]
[tex](2x+35)^\circ=90^\circ[/tex]
[tex]2x+35=90[/tex]
Subtract 35 from both sides.
[tex]2x=90-35[/tex]
[tex]2x=55[/tex]
[tex]x=\dfrac{55}{2}[/tex]
[tex]x=27.5[/tex]
The measure of smaller angle is 27.5 degrees.
Now, the measure of larger angle is:
[tex]\text{Larger angle}=(27.5+35)^\circ[/tex]
[tex]\text{Larger angle}=62.5^\circ[/tex]
Therefore, the measures of both angles are 27.5° and 62.5°.