Problem:
Suppose that γ is an angle with csc γ = -11/10 and γ is not in the third quadrant. Compute the exact value of cot γ. You do not have to rationalize the denominator.
Answer:
First let us draw your triangles
Then let's try to solve your problem
Sin(g) = -3/4: you should need to draw the point (x,y) such that y = -3, x <0, and x2 + (-3)2 = 42.
Then cos(g) = x/4, tan (g) = -3/x, csc (g) = -4/3,
sec(g) = 4/x and cot(g) = -x3.
Note:
The other one are done similarly: we can use other info to find the given figure out the (x,y) points, and derive the trig ratios from them.
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