Question

What is the concentration of a solution with a volume of 3.3 mL that contains 12 g of ammonium sulfite? (molar mass = 100.154 g/mol)

Answer 1

Answer:

36.30 M

Explanation:

Given that:

Molar mass of ammonium sulfite (NH₄)₂ SO₃ = 100.154 g/mol

Volume = 3.3 mL

to liters, we have: (3.3/1000)L

= 0.0033 L

mass = 12 grams

The concentration of the solution = $\dfrac{12 \ g}{ 100 .154 \ g/mol}\times \dfrac{1}{0.0033 \ L}$

= 36.30 M