If mAD = (17x + 2)°, mAC = (7x - 10°), and m∠ABC = (4x + 15)°, find m∠ABC
Please help
![If mAD 17x 2 mAC 7x 10 and mABC 4x 15 find mABC Please help class=](https://us-static.z-dn.net/files/d9d/9e69c13864455d4de17f0ad809721b9c.jpg)
Answer:
m<ABC = 51degrees
Step-by-step explanation:
The angle at the vertex is half the difference of the angles at the intercepted arcs. Hence;
m<B = 1/2 (arcAD - arcAC)
<ABC = 1/2(17x + 2 -(7x - 10°))
4x + 15 = 1/2(17x-7x+2+10)
2(4x+15) = 10x+12
8x + 30 = 10x+12
8x-10x = 12-30
-2x = -18
x = 18/2
x = 9
Get m<ABC
m<ABC = 4x + 15
m<ABC = 4(9) + 15
m<ABC = 36 + 15
m<ABC = 51degrees