Answer:
The right answer is "335.18 Hz".
Explanation:
Given:
Velocity of observer,
[tex]v_0=38 \ m/s[/tex]
Velocity of source,
[tex]v_s=31 \ m/s[/tex]
Frequency,
[tex]f=411 \ Hz[/tex]
As we know,
⇒ [tex]F=(\frac{v-v_0}{v+v_s} )\times f[/tex]
[tex]=(\frac{343-38}{343+31} )\times 411[/tex]
[tex]=(\frac{305}{374} )\times 411[/tex]
[tex]=0.815\times 411[/tex]
[tex]=335.18 \ Hz[/tex]