Given m\parallel nm∥n, find the value of x and y.
m
n
(5x-16)°
(7x+4)°
(6y-4)°
![Given mparallel nmn find the value of x and y m n 5x16 7x4 6y4 class=](https://us-static.z-dn.net/files/df9/398f92c49f6d390b94922d82e2cf8ad3.png)
Answer:
[tex]x=16^o[/tex]
[tex]y=20[/tex]
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[tex]To ~find ~X:-[/tex]
[tex]7x+4+5x-16=180[/tex]
[tex]12x=180+12[/tex]
[tex]12x=192[/tex]
[tex]x=16[/tex]
[tex]To~find~Y:-[/tex]
[tex]6y-4=116[/tex]
[tex]6y=120[/tex]
[tex]y=20[/tex]
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have a great day!!
The value of x and y is 16 and 20.
7x + 4+ 5x - 16 = 180
12x = 180 + 12
12x = 192
x = 16
Now
6y - 4 = 116
6y = 120
y = 20
Learn more: brainly.com/question/17429689