Question

the system of equations kx-5y = 2, 6x+2y = 7 has no solution, then k =

(a) -10 (b) -5 (c) -6 (d) -15​

Answer 1

Answer:

(d) -15

Step-by-step explanation:

Given system of equations are:

$\begin{cases}kx-5y=2\\\\6x+2y=7\end{cases}$

Since, given system of equations have no solution.

$\therefore \frac{k}{6}=\frac{-5}{2} \neq\frac{2}{7}$

$\implies \frac{k}{6}=\frac{-5}{2}$

$\implies k=\frac{6(-5)}{2}$

$\implies k=\frac{-30}{2}$

$\implies k=-15$