A cylindrical cake with a height of 5 inches has a 30 degree slice removed. If the volume of the removed slice is 40 inches what is the approximate radius of the cake

Respuesta :

Answer: [tex]5.52\ in.[/tex]

Step-by-step explanation:

Given

Height of cylindrical cake is [tex]h=5\ in.[/tex]

[tex]30^{\circ}[/tex] slice is removed

Volume of the slice is [tex]V=40\ in.^3[/tex]

Area of slice is

[tex]\Rightarrow \dfrac{30^{\circ}}{360^{\circ}}\times \pi r^2\\\\\Rightarrow \dfrac{\pi r^2}{12}[/tex]

Volume of slice will be multiplication of area and height

[tex]\Rightarrow V=A\times h\\\\\Rightarrow 40=\dfrac{\pi r^2}{12}\times 5\\\\\Rightarrow \pi r^2=\dfrac{40\times 12}{5}\\\\\Rightarrow r^2=\dfrac{40\times 12}{3.142\times 5}\\\\\Rightarrow r^2=30.55\\\Rightarrow r=5.52\ in.[/tex]

Hence, the radius of the cake is [tex]5.52\ in.[/tex]

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