Respuesta :

9514 1404 393

Answer:

  C

Step-by-step explanation:

A root with a given index is the same as a fractional power with that index as the denominator.

  [tex]\dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}=6^{\frac{1}{4}}2^{-\frac{1}{3}}=\sqrt[12]{(6^{\frac{1}{4}}2^{-\frac{1}{3}})^{12}}=\sqrt[12]{6^32^{-4}}\\\\=\sqrt[12]{6^32^82^{-12}}=\dfrac{\sqrt[12]{6^32^8}}{2}=\boxed{\dfrac{\sqrt[12]{55296}}{2}}[/tex]

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