Respuesta :

gmany

Answer:

[tex]\huge\boxed{\tan C=\dfrac{9}{12}}[/tex]

Step-by-step explanation:

[tex]sine=\dfrac{opposite}{hypotenuse}[/tex]

We have:

[tex]opposite=9\\hypotenuse=15[/tex]

Substitute:

[tex]\sin C=\dfrac{9}{15}[/tex]

[tex]cosine=\dfrac{adjacent}{hypotenuse}[/tex]

We have:

[tex]adjacent=12\\hypotenuse=15[/tex]

Substitute:

[tex]\cos C=\dfrac{12}{15}[/tex]

[tex]tangent=\dfrac{opposite}{adjacent}[/tex]

We have:

[tex]opposite=9\\adjacent=12[/tex]

Substitute:

[tex]\tan C=\dfrac{9}{12}[/tex]

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