Answer:
[tex]\text{D) }\frac{15}{17}[/tex]
Step-by-step explanation:
In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse of the triangle (o/h).
Therefore, we have:
[tex]\sin 62^{\circ}=\boxed{\text{D) }\frac{15}{17}}[/tex]
