Answer:
Zeros are 3 and 1.
GIVEN:
P(x) = x²-4x+3
TO FIND:
Zeros and to verify the relationship between zeros and coefficients.
SOLUTION:
=> x²-4x+3 = 0
=> x²-3x-x+3 = 0
=> (x²-3x)+(-x+3) = 0
=> x(x-3)-1(x-3) = 0
=> (x-3)(x-1) = 0
Either (x-3) = 0
=> x = 3
Either (x-1) = 0
=> x = 1
Formula:
=> Sum of zeroes (α+β) = -(Coefficient of x)/Coefficient of x²
=> Product of zeroes (αβ) = Constant term/ Coefficient of x²
Sum of zeros:
= 3+1
=> -(-4)/1 = -(Coefficient of x)/Coefficient of x²
Product of zeros:
= 3(1)
=> 3/1 = Constant term/ Coefficient of x²
the answer is 3 and 1
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