Answer:
Size of the side of the square = 25
Step-by-step explanation:
Here WY is the diagonal
VZ = ZX = 15
and VW = VY = 20 (bisector of diagonal)
The diagonals intersect each other at 90 degrees
Hence the side of the Rhombus
Sqrt ( 15^2 + 20^2)
Sqrt (225 +400)
Sqrt (625)
= 25