Answer:
(3,3)
Step-by-step explanation:
Linear equations of lines are given in the form:
y = mx + b;
where m is the slope of the line, b is the y intercept and x, y are variables.
From the graph, we can see that line 1 passes through (0,6) and (6,0) while line 2 passes through (0, 1) and (6, 5).
The equation of line 1 is given as:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-6=\frac{0-6}{6-0} (x-0)\\\\y=-x + 6\ \ \ (1)[/tex]
The equation of line 2 is given as:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-1=\frac{5-1}{6-0} (x-0)\\\\y=\frac{2}{3}x + 1\ \ \ (2)[/tex]
Solving equation 1 and 2 simultaneously by subtracting equation 1 from 2 gives:
(5/3)x - 5 = 0
(5/3)x = 5
x = 3
Put x = 3 in equation 1:
y = -3 + 6 = 3
Therefore the two lines meet at (3, 3).