Answer:
The gases in a hair spray can are at a temperature of 26.0 °C and a pressure of 25.0 lbs/in2.
If the pressure becomes [tex]90.0lbs/in^{2}[/tex], what is the temperature of the gases?
Explanation:
According to Gay lussac's law:
the pressure of a gas is directly proportional to its absolute temperature.
[tex]P\alpha T[/tex]
[tex]\frac{P{1} }{T{1} }=\frac{P{2} }{T{2} }[/tex]
Given,
[tex]P1=25.0lbs/in^{2} \\P2=90.0lbs/in^{2} \\T1=26^{o} C=(26+273)K=299K\\T2=?[/tex]
Substitute these values in the above formula:
[tex]\frac{P{1} }{T{1} }=\frac{P{2} }{T{2} }\\\\\frac{25lbs/in^{2} }{299K} }=\frac{90.0lbs/in^{2} }{T{2} }\\\\\\On simplification \\T2=1076.4K\\T2=(1076.4-273)^{o} C=803.4^{o} C[/tex]
Answer:
The gases will be raised to a temperature of 803.4[tex]^{o} C[/tex].