Question

Find the distance between the points (5, 6) and (5, - 4).

Answer 1

Answer:

Step-by-step explanation:

using formula

x1=5 , x2=5 , y1=6 , y2=-4

distance = $\sqrt{(x2-x1)^{2}+(y2-y1)^{2} }$

=$\sqrt{(5-5)^{2}+(4-6^{2} }$

=$\sqrt{(0)^{2}+(-2)^{2} }$

=$\sqrt{0+4}$

=$\sqrt{4}$

=2 units

Answer 2

Answer:

10 units

Step-by-step explanation:

(5, 6) and (5, - 4)

To find the distance between two points, we use the distance formula:

$d = \sqrt{(x_{2}-x_1)^2 + (y_2-y_1)^2 }$

Let's plug in what we know.

$d = \sqrt{(5-5)^2 + (-4-6)^2 }$

Evaluate the parentheses.

$d = \sqrt{(0)^2 + (-10)^2 }$

Evaluate the exponents.

$d = \sqrt{(0) + (100) }$

Add.

$d=\sqrt{100}$

Evaluate the radical.

d = ±10

Since distance cannot be negative, you answer is 10 units.

Hope this helps!