Given:
Consider the given expression is:
[tex]\dfrac{7^{-1}}{7^{-2}}[/tex]
To find:
The quotient of the given fraction value.
Solution:
We have,
[tex]\dfrac{7^{-1}}{7^{-2}}[/tex]
It can be written as:
[tex]\dfrac{7^{-1}}{7^{-2}}=7^{-1-(-2)}[/tex] [tex]\left[\because \dfrac{a^m}{a^n}=a^{m-n}\right][/tex]
[tex]\dfrac{7^{-1}}{7^{-2}}=7^{-1+2}[/tex]
[tex]\dfrac{7^{-1}}{7^{-2}}=7^{1}[/tex]
[tex]\dfrac{7^{-1}}{7^{-2}}=7[/tex]
Therefore, the value of the quotient is 7.
Note: Options B and C are same and both are correct.
