Answer:
(a) convex mirror
(b) virtual and magnified
(c) 23.3 cm
Explanation:
The having mirror is convex mirror.
distance of object, u = - 20 cm
magnification, m = 1.4
(a) As the image is magnified and virtual , so the mirror is convex in nature.
(b) The image is virtual and magnified.
(c) Let the distance of image is v.
Use the formula of magnification.
[tex]m =-\frac{v}{u}\\1.4=-\frac{v}{-20}\\v =28 cm[/tex]
Use the mirror equation, let the focal length is f.
[tex]\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\frac{1}{f}=\frac{1}{28}+\frac{1}{20}\\\frac{1}{f}=\frac{28+20}{560}\\f=11.67cm[/tex]
Radius of curvature, R = 2 f = 2 x 11.67 = 23.3 cm