You leave from (-2, 1) near the ball court and head to (5,0) at the Templo Mayor to pay your respects to the gods. How many units did you travel?​

Respuesta :

Space

Answer:

[tex]\displaystyle d = 5\sqrt{2}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Algebra I

  • Coordinates (x, y)

Algebra II

  • Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

Point (-2, 1)

Point (5, 0)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

  1. Substitute in points [Distance Formula]:                                                         [tex]\displaystyle d = \sqrt{(5--2)^2+(0-1)^2}[/tex]
  2. [√Radical] (Parenthesis) Subtract:                                                                   [tex]\displaystyle d = \sqrt{(7)^2+(-1)^2}[/tex]
  3. [√Radical] Evaluate exponents:                                                                       [tex]\displaystyle d = \sqrt{49+1}[/tex]
  4. [√Radical] Add:                                                                                                 [tex]\displaystyle d = \sqrt{50}[/tex]
  5. [√Radical] Simplify:                                                                                           [tex]\displaystyle d = 5\sqrt{2}[/tex]
msm555

Answer:

Solution given:

(x1,y1)=(-2,1)

(x2,y2)=(5,0)

distance=?

we have

distance=[tex] \sqrt{(x2-x1) ²+(y2-y1) ²}[/tex]

d=[tex] \sqrt{(5+2)²+(0-1) ²}[/tex]

d=[tex] \sqrt{50}[/tex]

d=[tex] 5\sqrt{2}[/tex]units

[tex] 5\sqrt{2}[/tex]units I travelled.

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