Question

How many mL of 8.00M HCl solution are needed to make a dilution with a final volume of 2,500.ml, and a
concentration of HC-0.333M?

Answer 1

Answer:

104.1 mL

Explanation:

c1V1 = c2V2

V1 = c2V2/c1 = (0.333 M×2500 mL)/8.00 M

V1 = 104.1 mL