Answer:
y + 1 = 5/3(x + 8)
or
y - 9 = 5/3(x + 2)
*both work
Step-by-step explanation:
First, we can start by finding the slope of the line, which can be represented as:
[tex]\frac{y_{2}-y_{1} }{x_{2} -x_{1} }[/tex]
We can substitute in the points (-8, -1) and (-2, 9):
[tex]\frac{9-(-1)}{-2-(-8)}[/tex]
And we can simplify
[tex]\frac{9+1}{-2+8}[/tex]
[tex]\frac{10}{6}=\frac{5}{3}[/tex]
The point-slope equation of a line can be written as:
[tex]y-y_{1} =m(x-x_{1} )[/tex]
We can either use the point (-8, -1) or (-2, 9). It doesn't matter which one we use.
For the point (-8, -1), you get:
y + 1 = 5/3(x + 8)
For the point (-2, 9) you get:
y - 9 = 5/3(x + 2)
