Answer:
Step-by-step explanation:
IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. What is the probability that a randomly chosen person's IQ score will be between 101 and 134, to the nearest thousandth
z = (x-μ)/σ, where x is the raw score,
μ is the population mean = 100
σ is the population standard deviation = 15
For x = 101
z = 101 - 100/15
z = 0.066667
Probability value from Z-Table:
P(x = 101) = 0.52658
For x = 134
z = 134 - 100/15
z = 2.26667
Probability value from Z-Table:
P(x= 134) = 0.98829
Therefore,
