Question

The lengths of the 2 diagonal of a rhombus are 24cm and 32cm what is the length of one side of the rhombus. ​

Answer 1

Answer:

$height = \frac{24}{2} = 12 \: cm \\ adjacent = \frac{32}{2} = 16 \: cm$

We get a triangle of height 12 cm and adjacent 16 cm

$side = \sqrt{ {12}^{2} + {16}^{2} } \\ = \sqrt{400} \\ = 20 \: cm$

Answer 2

Answer:

side=√(24/2)²+(32/2)²

=√12²+16²

=√400

= 20