quirkss
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PLEASE!! I JUST REALLY NEED SOME HELP RIGHT NOW!! T∆T
Using the 45o -45o -90o triangle theorem, solve this triangle.​

PLEASE I JUST REALLY NEED SOME HELP RIGHT NOW TTUsing the 45o 45o 90o triangle theorem solve this triangle class=

Respuesta :

Answer:

Step-by-step explanation:

take 45 degree as reference angle

using sin rule

sin 45=opposite/hypotenuse

1/[tex]\sqrt{2}[/tex]=l/11[tex]\sqrt{2}[/tex] (do cross multiplication)

l[tex]\sqrt{2}[/tex]=11[tex]\sqrt{2}[/tex]

l=11[tex]\sqrt{2}[/tex]/[tex]\sqrt{2}[/tex]

l=11

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