Question

find the positive value of p if the expression 2x²-px+p leaves a remainder 6 when divided by x-p​

Answer 1

Explanation:

$f(x) = 2x^2 -px + p\\given \ f(x) \ \ leaves ] remainder \ when \ divided \ by \ x - p \\\\Therefore, \\\\f(p) = 6\\\\=> f(p) = 2(p)^2 -p(p) + p = 6\\\\==>2(p)^2 - p^2 + p = 6\\\\=> p^2 + p - 6 = 0\\\\=>p^2 + 3p - 2p -6 = 0\\\\p(p+3)-2(p+3) =0 \\\\(p-2)(p+3) = 0\\\\p = 2, -3$

Answer : p = 2