Question

Determine the smallest integer value of x in the solution of the following inequality.

-3x+10≤5

Answer 1

Answer: The smallest integer value of x in the solution is 1.

Step-by-step explanation:

The given inequality: $-3x+10\leq5$

To solve the inequality, we first subtract 10 from both sides

$-3x+10-10\leq5-10\\\\\Rightarrow\ -3x\leq-5$

Multiply negative sign on both sides ,we get

$3x\geq5$

Divide both sides by 3, we get

$x\geq\frac{5}{3}$

i.e. $x\geq 1.6666666667$

$x\geq1$

Hence, the smallest integer value of x in the solution is 1.