Solve the right triangle. Round decimal answers to the nearest tenth.
PLS PLSS HELPPPP 25 POINTSSS

Answer:
Step-by-step explanation:
[tex]14^2 = b^2+6^2\\b^2 = 14^2-6^2\\b = \sqrt{14^2-6^2} \\ = \sqrt{160}\\ = 12.6491106407[/tex]
Rounding off to nearest tenth:
b ≈ 12.6
tanθ = 6/12.6
[tex]tan^{-1} (6/12.6)\\ = 25.46334506\\[/tex]
Hence angle A ≈ 25.5
Angle B = 180-25.5-90
Angle B = 64.53665494
Hence, Angle B ≈ 64.5
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