Respuesta :

Answer:

[tex]x = \frac{12}{ \tan(60 \degree) } \\ x = \frac{12}{ \sqrt{3} } \\ x = 4 \sqrt{3} \: cm[/tex]

[tex]y = \frac{12}{ \sin (60 \degree) } \\ y = \frac{12 \times 2}{ \sqrt{3} } \\ y = \frac{24}{ \sqrt{3} } \\ y = 8 \sqrt{3} \: cm[/tex]

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