[tex] [\frac{7}{12} + ( - \frac{5}{12} )] -[ \frac{5}{9} + ( - \frac{2}{9} )] \\ \\ = [ \frac{7}{12} - \frac{5}{12} ] - [ \frac{5}{9} - \frac{2}{9} ] \\ \\ = [ \frac{7 - 5}{12} ] - [ \frac{5 - 2}{9} ] \\ \\ = \frac{2}{12} - \frac{3}{9} \\ \\ = \cancel \frac{2}{12} - \cancel \frac{3}{9} \\ \\ = \frac{1}{6} - \frac{1}{3} \\ \\ = \frac{1 - 2}{6} \\ \\ = - \frac{1}{6} [/tex]
Answer:
[tex]\frac{-1}{6}[/tex]
Step-by-step explanation:
[tex]Sum \ of \ \ \frac{5}{9} \ and \ \frac{-2}{9} =\frac{5}{9} + \frac{-2}{9} = \frac{5-2}{9} = \frac {3}{9} = \frac{1}{3}[/tex]
[tex]Sum \ of \ \frac{7}{12} \ and \ \frac{-5}{12} = \frac{7}{12} \ + \ \frac{-5}{12} = \frac{7-5}{12} = \frac{2}{12} = \frac{1}{6}[/tex]
[tex]subtract \ first \ from \ second = \frac{1}{6} - \frac{1}{3} = \frac{1 -2}{6} = \frac{-1}{6}[/tex]
