Answer:0.65
Explanation:
Moles of sodium hydroxide = Moles of sodiumExplanation:So all we have to do is calculate the molar quantity of sodium, which is the same as the molar quantity of sodium hydroxide. How do I know this? Because you have kindly included the balanced equation, which shows a 1:1 equivalence between the metal and its hydroxide salt, and a 2:1 equivalence between the metal and the gas it has produced. Moles of sodium = 15.0⋅g22.99⋅g⋅mol−1 = 0.652⋅mol.Given the stoichiometry of the reaction, clearly 0.652⋅mol sodium hydroxide will result.How many grams of sodium hydroxide will this represent? What is the molar quantity of dihydrogen that will result, and what volume will it occupy under conditions of 1⋅atm and 298⋅K?
