If the index of refraction for a certain glass is 1.5, and the angle of refraction is 15 degrees for a ray of light
traveling from air (index of 1) what is the angle of incidence? (in coming beam)
Round your answer to the nearest tenth of a digit. The answer is in degrees so don't worry about the units

Respuesta :

Answer:

[tex]\theta_i = 23^o[/tex]

Explanation:

The refractive index of a medium is given by the following formula:

[tex]\eta = \frac{Sin\theta_i}{Sin\theta_r}[/tex]

where,

η = refractive index = 1.5

[tex]\theta_i[/tex] = angle of incidence = ?

[tex]\theta_r[/tex] = angle of refraction = 15°

Therefore,

[tex]1.5 = \frac{Sin\theta_i}{Sin15^o}\\\\Sin\theta_i=(1.5)Sin15^o\\\\\theta_i = Sin^{-1}(0.388)\\\\[/tex]

[tex]\theta_i = 23^o[/tex]

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