Answer:
Explanation:
solve the parallel resistances
30||40 and 50||30
17.14285714 and 18.75
total Resistance = 35.89285714
V = IR
9V = I *35.89285714
9V / 35.89285714 = I
0.250746 = I
Now use the resistance across AB
V = 17.14285714 * 0.250746
V = 4.29850
this is the Voltage drop across AB :P
