Respuesta :

Answer:

[tex]\rho=12g/cm^3[/tex]

Explanation:

From the question we are told that:

Length[tex]l=379.0pm=>379*10^{-10}cm[/tex]

Atomic mass of X [tex]M= 195.0 amu=>gmol^{-1}[/tex]

Where

[tex]Avogadro\ constant = 6.023 * 10^{23} mol-1[/tex]

Let

The Number of units in BCC unit cell [tex]n= 2[/tex]

Generally the equation for Density is mathematically given by

[tex]\rho= \frac{M x n}{l^3*Avogadro constant}[/tex]

[tex]\rho=\frac{197 x 2}{(379*10^{-10})^3*6.023 x 10^{23}}[/tex]

[tex]\rho=12g/cm^3[/tex]

Therefore he density of Xin g/cc

[tex]\rho=12g/cm^3[/tex]

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