9514 1404 393
Answer:
D
Step-by-step explanation:
The result will be the root of each coefficient, and each exponent cut in half.
[tex]\sqrt{\dfrac{4j^4}{9k^8}}=\sqrt{\dfrac{2^2}{3^2}}\sqrt{\left(\dfrac{j^2}{k^4}\right)^2}=\boxed{\dfrac{2j^2}{3k^4}}[/tex]
