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Answer: what

Step-by-step explanation:

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TS is diameter of the circle, and we know that a diameter forms 90° angle at the circumference of the circle.

So, Triangle TRS is a Right angled triangle.

let's take radius of the circle as x

TS = 2x

Applying Pythagoras theorem :

  • [tex] \mathrm{TS²= TR²+SR²}[/tex]

  • [tex](2x) {}^{2} = {6}^{2} + {8}^{2} [/tex]

  • [tex]4 {x}^{2} = 36 + 64[/tex]

  • [tex] {x}^{2} = \dfrac{100}{4} [/tex]

  • [tex] {x}^{2} = 25[/tex]

  • [tex]x = \sqrt{25} [/tex]

  • [tex]x = 5[/tex]

Therefore radius of circle is :

[tex] \large \boxed{5 \: in}[/tex]

Now, Area of circle :

[tex] \large\boxed{\pi {r}^{2} }[/tex]

  • [tex]\pi \times 5 \times 5[/tex]

  • [tex]25\pi \: \: in {}^{2} [/tex]

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